"자코비 삼중곱(Jacobi triple product)"의 두 판 사이의 차이

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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">이 항목의 스프링노트 원문주소</h5>
  
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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">개요</h5>
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<math>\sum_{n=-\infty}^\infty  z^{n}q^{n^2}= \prod_{m=1}^\infty  \left( 1 - q^{2m}\right) \left( 1 + zq^{2m-1}\right) \left( 1 + z^{-1}q^{2m-1}\right)</math>
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<math>z=1</math> 인 경우
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<math>\sum_{n=-\infty}^\infty q^{n^2}= \prod_{m=1}^\infty  \left( 1 - q^{2m}\right) \left( 1 + q^{2m-1}\right)^2</math>
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(증명)
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[[q-초기하급수(q-hypergeometric series) (통합됨)|q-초기하급수(q-hypergeometric series)]]
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<math>\prod_{n=0}^{\infty}(1+zq^n)=\sum_{n\geq 0}\frac{q^{n(n-1)/2}}{(1-q)(1-q^2)\cdots(1-q^n)} z^n</math>
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<math>\prod_{n=0}^{\infty}\frac{1}{1+zq^n}=\sum_{n\geq 0}\frac{(-1)^n}{(1-q)(1-q^2)\cdots(1-q^n)} z^n</math>
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를 활용
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<math>\prod_{m=0}^\infty  \left( 1 + zq^{2m+1}\right)=\sum_{n\geq 0}\frac{q^nz^n}{(1-q^2)(1-q^4)\cdots(1-q^{2n})}</math>
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'''[Andrews65] '''참조 ■
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<h5>재미있는 사실</h5>
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* Math Overflow http://mathoverflow.net/search?q=
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* 네이버 지식인 http://kin.search.naver.com/search.naver?where=kin_qna&query=
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<h5>역사</h5>
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* http://www.google.com/search?hl=en&tbs=tl:1&q=
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* [http://jeff560.tripod.com/mathword.html Earliest Known Uses of Some of the Words of Mathematics]
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* [http://jeff560.tripod.com/mathsym.html Earliest Uses of Various Mathematical Symbols]
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* [[수학사연표 (역사)|수학사연표]]
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<h5>메모</h5>
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<h5>관련된 항목들</h5>
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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">수학용어번역</h5>
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* 단어사전 http://www.google.com/dictionary?langpair=en|ko&q=
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* 발음사전 http://www.forvo.com/search/
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* [http://mathnet.kaist.ac.kr/mathnet/math_list.php?mode=list&ftype=&fstr= 대한수학회 수학 학술 용어집]<br>
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** http://mathnet.kaist.ac.kr/mathnet/math_list.php?mode=list&ftype=eng_term&fstr=
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* [http://www.nktech.net/science/term/term_l.jsp?l_mode=cate&s_code_cd=MA 남·북한수학용어비교]
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* [http://kms.or.kr/home/kor/board/bulletin_list_subject.asp?bulletinid=%7BD6048897-56F9-43D7-8BB6-50B362D1243A%7D&boardname=%BC%F6%C7%D0%BF%EB%BE%EE%C5%E4%B7%D0%B9%E6&globalmenu=7&localmenu=4 대한수학회 수학용어한글화 게시판]
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<h5>사전 형태의 자료</h5>
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* http://ko.wikipedia.org/wiki/
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* http://en.wikipedia.org/wiki/
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* http://www.proofwiki.org/wiki/
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* http://www.wolframalpha.com/input/?i=
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* [http://eom.springer.de/default.htm The Online Encyclopaedia of Mathematics]
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* [http://dlmf.nist.gov/ NIST Digital Library of Mathematical Functions]
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* [http://www.research.att.com/%7Enjas/sequences/index.html The On-Line Encyclopedia of Integer Sequences]
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<h5>관련논문</h5>
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* '''[Andrews65]'''[http://www.jstor.org/stable/2033875 Shorter Notes: A Simple Proof of Jacobi's Triple Product Identity]<br>
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** George E. Andrews, Proceedings of the American Mathematical Society, Vol. 16, No. 2 (Apr., 1965), pp. 333-334
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* [http://www.jstor.org/stable/2320552 An Easy Proof of the Triple-Product Identity]<br>
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** John A. Ewell, <cite style="line-height: 2em;">[http://www.jstor.org/action/showPublication?journalCode=amermathmont The American Mathematical Monthly]</cite>, Vol. 88, No. 4 (Apr., 1981), pp. 270-272
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* http://www.jstor.org/action/doBasicSearch?Query=
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* http://www.ams.org/mathscinet
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* http://dx.doi.org/
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<h5>관련도서</h5>
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*  도서내검색<br>
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** http://books.google.com/books?q=
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** http://book.daum.net/search/contentSearch.do?query=
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*  도서검색<br>
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** http://books.google.com/books?q=
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** http://book.daum.net/search/mainSearch.do?query=
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** http://book.daum.net/search/mainSearch.do?query=
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<h5>관련기사</h5>
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*  네이버 뉴스 검색 (키워드 수정)<br>
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** http://news.search.naver.com/search.naver?where=news&x=0&y=0&sm=tab_hty&query=
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** http://news.search.naver.com/search.naver?where=news&x=0&y=0&sm=tab_hty&query=
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** http://news.search.naver.com/search.naver?where=news&x=0&y=0&sm=tab_hty&query=
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<h5>링크</h5>
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*  구글 블로그 검색<br>
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** http://blogsearch.google.com/blogsearch?q=
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* [http://navercast.naver.com/science/list 네이버 오늘의과학]
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* [http://www.ams.org/mathmoments/ Mathematical Moments from the AMS]
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* [http://betterexplained.com/ BetterExplained]
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* [http://www.exampleproblems.com/ exampleproblems.com]

2010년 12월 29일 (수) 10:05 판

이 항목의 스프링노트 원문주소

 

 

개요

 

 

\(\sum_{n=-\infty}^\infty z^{n}q^{n^2}= \prod_{m=1}^\infty \left( 1 - q^{2m}\right) \left( 1 + zq^{2m-1}\right) \left( 1 + z^{-1}q^{2m-1}\right)\)

 

\(z=1\) 인 경우

\(\sum_{n=-\infty}^\infty q^{n^2}= \prod_{m=1}^\infty \left( 1 - q^{2m}\right) \left( 1 + q^{2m-1}\right)^2\)

 

(증명)

q-초기하급수(q-hypergeometric series)

\(\prod_{n=0}^{\infty}(1+zq^n)=\sum_{n\geq 0}\frac{q^{n(n-1)/2}}{(1-q)(1-q^2)\cdots(1-q^n)} z^n\)

\(\prod_{n=0}^{\infty}\frac{1}{1+zq^n}=\sum_{n\geq 0}\frac{(-1)^n}{(1-q)(1-q^2)\cdots(1-q^n)} z^n\)

를 활용

 

\(\prod_{m=0}^\infty \left( 1 + zq^{2m+1}\right)=\sum_{n\geq 0}\frac{q^nz^n}{(1-q^2)(1-q^4)\cdots(1-q^{2n})}\)

[Andrews65] 참조 ■

 

 

 

 

재미있는 사실

 

 

 

역사

 

 

 

메모

 

 

관련된 항목들

 

 

수학용어번역

 

 

사전 형태의 자료

 

 

관련논문

 

 

관련도서

 

 

관련기사

 

 

링크