"Ramanujan's Cubic Continued fractions"의 두 판 사이의 차이

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<math>{1 \over 1+} {q+q^2 \over 1+} {q^4 \over 1+} {q^3+q^6 \over 1+}{q^8 \over 1+\cdots} =\frac{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}</math>
  
 
 
 
 

2010년 7월 22일 (목) 04:23 판

introduction

\({1 \over 1+} {q+q^2 \over 1+} {q^4 \over 1+} {q^3+q^6 \over 1+}{q^8 \over 1+\cdots} =\frac{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}\)

 

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encyclopedia

 

 

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[[4909919|]]

 

 

articles
  • RAMANUJAN’S CUBIC CONTINUED FRACTION AND RAMANUJAN TYPE CONGRUENCES FOR A CERTAIN PARTITION FUNCTION
    • HEI-CHI CHAN
  • A NEW PROOF FOR TWO IDENTITIES INVOLVING RAMANUJAN’S CUBIC CONTINUED FRACTION
    • HEI-CHI CHAN
  • On Ramanujan’s cubic continued fraction
    • Heng Huat Chan (Urbana, Ill.)

 

http://www.emis.de/journals/ETNA/vol.25.2006/pp158-165.dir/pp158-165.pdf

 

 

Ramanujan's class invariants and cubic continued fraction

Berndt, 1995

 

 

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