"Vertex operator algebra (VOA)"의 두 판 사이의 차이

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잔글 (찾아 바꾸기 – “<h5>” 문자열을 “==” 문자열로)
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잔글 (찾아 바꾸기 – “</h5>” 문자열을 “==” 문자열로)
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==definition</h5>
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==definition==
  
 
* vertex operator algbera is a quadruple <math>(V,Y,\mathbf{1},\omega)</math> with the following axioms
 
* vertex operator algbera is a quadruple <math>(V,Y,\mathbf{1},\omega)</math> with the following axioms
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==vertex algebra vs VOA</h5>
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==vertex algebra vs VOA==
  
 
* grading on V
 
* grading on V
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==axioms</h5>
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==axioms==
  
 
*   <br><math>u_{n}v=0</math> for <math>n>>0</math><br>
 
*   <br><math>u_{n}v=0</math> for <math>n>>0</math><br>
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==remark on Jacobi identity</h5>
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==remark on Jacobi identity==
  
 
*  Jacobi identity for Lie algebra says<br><math>(\operatorname{ad} u)(\operatorname{ad} v)-(\operatorname{ad} v)-(\operatorname{ad} u)=(\operatorname{ad}(\operatorname{ad} u) v)</math><br>
 
*  Jacobi identity for Lie algebra says<br><math>(\operatorname{ad} u)(\operatorname{ad} v)-(\operatorname{ad} v)-(\operatorname{ad} u)=(\operatorname{ad}(\operatorname{ad} u) v)</math><br>
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==history</h5>
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==history==
  
 
* http://www.google.com/search?hl=en&tbs=tl:1&q=
 
* http://www.google.com/search?hl=en&tbs=tl:1&q=
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==related items</h5>
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==related items==
  
 
 
 
 
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<h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">encyclopedia</h5>
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<h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">encyclopedia==
  
 
* http://en.wikipedia.org/wiki/
 
* http://en.wikipedia.org/wiki/
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==books</h5>
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==books==
  
 
 
 
 
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==expositions</h5>
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==expositions==
  
 
 
 
 
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<h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">articles</h5>
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<h5 style="line-height: 3.428em; margin: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">articles==
  
 
 
 
 
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==question and answers(Math Overflow)</h5>
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==question and answers(Math Overflow)==
  
 
* http://mathoverflow.net/search?q=
 
* http://mathoverflow.net/search?q=
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==blogs</h5>
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==blogs==
  
 
*  구글 블로그 검색<br>
 
*  구글 블로그 검색<br>
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==experts on the field</h5>
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==experts on the field==
  
 
* http://arxiv.org/
 
* http://arxiv.org/
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==links</h5>
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==links==
  
 
* [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier]
 
* [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier]
 
* [http://pythagoras0.springnote.com/pages/1947378 수식표현 안내]
 
* [http://pythagoras0.springnote.com/pages/1947378 수식표현 안내]

2012년 10월 28일 (일) 16:04 판

definition

  • vertex operator algbera is a quadruple \((V,Y,\mathbf{1},\omega)\) with the following axioms
  • \(V=\bigoplus_{n\in\mathbb{Z}}V_{(n)}\) vector space
  • \(\dim V_{(n)} <\infty\) for \(n\in \mathbb{Z}\)
  • \(\dim V_{(n)}=0\) for \(n<<0\)
  • vertex operator
    \(V\to (\operatorname{End})[[x,x^{-1}]]\)
    \(v\mapsto Y(v,x)=\sum_{n\in \mathbb{Z}}v_{n}x^{-n-1}\)
  • two distinguished vectors \(\mathbf{1}\in V_{(0)}\) and  \(\omega\in V_{(2)}\)

 

 

vertex algebra vs VOA

  • grading on V

 

 

axioms

  •  
    \(u_{n}v=0\) for \(n>>0\)
  • \(Y(\mathbf{1},z)=\operatorname{id}_{V}\)
  • (creation property)
    \(Y(v,z).\mathbf{1}=v+\cdots\)
  • conformal vector
    \(Y(\omega,z)=L(z)=\sum L(n)z^{-n-2}\) satisfies
    \([L_m,L_n]=(m-n)L_{m+n}+\frac{c}{12}(m^3-m)\delta_{m+n}\)
  • \(L(0)v=nv\) for \(n\in\mathbb{Z}\) and \(v\in V_{(n)}\)
  • translation covariance  
    \([D, Y(v,z)]=\sum_{n}[D,V_n]z^{-n-1}=\partial Y(v,z)\)
  • Jacobi identity
    \( $z_0^{-1}\delta(\frac {z_1-z_2}{z_0})Y(u,z_1)Y(v,z_2)-z_0^{-1}\delta(\frac {z_2-z_1}{-z_0})Y(v,z_2)Y(u,z_1)=z_2^{-1}\delta\left(\frac {z_1-z_0}{z_2}\right)Y(Y(u,z_0)v,z_2)$\)

 

 

remark on Jacobi identity

  • Jacobi identity for Lie algebra says
    \((\operatorname{ad} u)(\operatorname{ad} v)-(\operatorname{ad} v)-(\operatorname{ad} u)=(\operatorname{ad}(\operatorname{ad} u) v)\)

 

 

history

 

 

related items

 

 

encyclopedia==    

books

 

 

 

expositions

 

 

articles==      

question and answers(Math Overflow)

 

 

 

blogs

 

 

experts on the field

 

 

links