"Ramanujan-Göllnitz-Gordon 연분수"의 두 판 사이의 차이
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Pythagoras0 (토론 | 기여) |
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| − | + | ==개요== | |
| − | * [ | + | * Göllnitz:<math>1+q+{q^{2} \over 1+q^{3} + } {q^{4} \over 1+q^{5}+} {q^{6} \over \cdots}=\frac{(q^{3};q^{8})_{\infty}(q^{4};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}{(q^{1};q^{8})_{\infty}(q^{4};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}=\frac{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}</math> |
| + | * '''[Gordon1965]''' | ||
| + | :<math>1+{q \over 1+q^2 + } {q^3 \over 1+q^4+} {q^5 \over 1+q^6} \cdots=\frac{(q^{2};q^{8})_{\infty}(q^{3};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{1};q^{8})_{\infty}(q^{5};q^{8})_{\infty}(q^{6};q^{8})_{\infty}}</math> | ||
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| − | + | ==라마누잔의 결과== | |
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| − | + | * Berndt, notebook V entry 22 p. 50:<math>{1 \over 1+} {q+q^2 \over 1+} {q^4 \over 1+} {q^3+q^6 \over 1+}{q^8 \over 1+\cdots} =\frac{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}</math> | |
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| − | + | ==모듈라 함수== | |
| − | + | * fractional power | |
| + | :<math>{q^{1/2} \over 1+q+} {q^2 \over 1+q^3 + } {q^4 \over 1+q^5 + } {q^6 \over 1+q^7+\cdots} =q^{1/2}\frac{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}</math> | ||
| + | * '''[Duke2005] '''(9.4) | ||
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| − | + | ==메모== | |
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* Math Overflow http://mathoverflow.net/search?q= | * Math Overflow http://mathoverflow.net/search?q= | ||
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| − | + | ==관련된 항목들== | |
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| − | + | ==리뷰논문, 에세이, 강의노트== | |
| − | * '''[ | + | * W. Duke '''[Duke2005]'''[http://www.ams.org/bull/2005-42-02/S0273-0979-05-01047-5/home.html#References Continued fractions and modular functions], Bull. Amer. Math. Soc. 42 (2005), 137-162 |
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| − | + | ==관련논문== | |
| + | * '''[Gordon1965]''' Basil Gordon [http://projecteuclid.org/euclid.dmj/1077376080 Some continued fractions of the Rogers-Ramanujan type], Duke Math. J. Volume 32, Number 4 (1965), 741-748. | ||
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| − | + | [[분류:q-급수]] | |
| − | + | [[분류:연분수]] | |
2020년 12월 28일 (월) 01:59 기준 최신판
개요
- Göllnitz\[1+q+{q^{2} \over 1+q^{3} + } {q^{4} \over 1+q^{5}+} {q^{6} \over \cdots}=\frac{(q^{3};q^{8})_{\infty}(q^{4};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}{(q^{1};q^{8})_{\infty}(q^{4};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}=\frac{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}\]
- [Gordon1965]
\[1+{q \over 1+q^2 + } {q^3 \over 1+q^4+} {q^5 \over 1+q^6} \cdots=\frac{(q^{2};q^{8})_{\infty}(q^{3};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{1};q^{8})_{\infty}(q^{5};q^{8})_{\infty}(q^{6};q^{8})_{\infty}}\]
라마누잔의 결과
- Berndt, notebook V entry 22 p. 50\[{1 \over 1+} {q+q^2 \over 1+} {q^4 \over 1+} {q^3+q^6 \over 1+}{q^8 \over 1+\cdots} =\frac{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}\]
모듈라 함수
- fractional power
\[{q^{1/2} \over 1+q+} {q^2 \over 1+q^3 + } {q^4 \over 1+q^5 + } {q^6 \over 1+q^7+\cdots} =q^{1/2}\frac{(q^{1};q^{8})_{\infty}(q^{7};q^{8})_{\infty}}{(q^{3};q^{8})_{\infty}(q^{5};q^{8})_{\infty}}\]
- [Duke2005] (9.4)
메모
- Math Overflow http://mathoverflow.net/search?q=
관련된 항목들
리뷰논문, 에세이, 강의노트
- W. Duke [Duke2005]Continued fractions and modular functions, Bull. Amer. Math. Soc. 42 (2005), 137-162
관련논문
- [Gordon1965] Basil Gordon Some continued fractions of the Rogers-Ramanujan type, Duke Math. J. Volume 32, Number 4 (1965), 741-748.