"PSLQ for dilogarithm identities"의 두 판 사이의 차이
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imported>Pythagoras0 |
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| (사용자 2명의 중간 판 13개는 보이지 않습니다) | |||
| 1번째 줄: | 1번째 줄: | ||
| − | + | ==introduction== | |
| + | * Implement the [[PSLQ algorithm]] first. | ||
| + | * I found | ||
| − | + | <math>-2L(1)+2L(\alpha)+2L(\alpha^{2})-L(\alpha^{4})=0</math> or | |
| − | + | <math>2L(\alpha)+2L(\alpha^{2})-L(\alpha^{4})=\frac{\pi^2}{3}</math> | |
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| − | + | ==related items== | |
| − | + | * [[PSLQ algorithm]] | |
| + | * [[Slater 34]] | ||
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| − | + | ==computational resource== | |
| + | * https://docs.google.com/file/d/0B8XXo8Tve1cxNW0ta2hCUVJPdmc/edit | ||
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| − | + | [[분류:개인노트]] | |
| − | + | [[Category:계산]] | |
| − | + | [[Category:quantum dimensions]] | |
| − | + | [[분류:dilogarithm]] | |
| − | + | [[분류:migrate]] | |
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2020년 11월 12일 (목) 22:53 기준 최신판
introduction
- Implement the PSLQ algorithm first.
- I found
\(-2L(1)+2L(\alpha)+2L(\alpha^{2})-L(\alpha^{4})=0\) or
\(2L(\alpha)+2L(\alpha^{2})-L(\alpha^{4})=\frac{\pi^2}{3}\)