"수식 표현 안내"의 두 판 사이의 차이
Pythagoras0 (토론 | 기여) |
Pythagoras0 (토론 | 기여) |
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* http://en.wikibooks.org/wiki/LaTeX | * http://en.wikibooks.org/wiki/LaTeX | ||
− | + | ===모르는 명령어 그림으로 알아내기=== | |
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− | ==모르는 명령어 그림으로 알아내기== | ||
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* [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier] | * [http://detexify.kirelabs.org/classify.html Detexify2 - LaTeX symbol classifier] | ||
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==LaTeX으로 노트하기== | ==LaTeX으로 노트하기== | ||
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* [http://math.berkeley.edu/%7Eanton/index.php?m1=me&m2=TeXadvice Advice on realtime TeXing] | * [http://math.berkeley.edu/%7Eanton/index.php?m1=me&m2=TeXadvice Advice on realtime TeXing] | ||
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* 한글 TeX http://ajt.ktug.kr/2007/0102khlee.pdf | * 한글 TeX http://ajt.ktug.kr/2007/0102khlee.pdf | ||
− | ==LaTeX | + | ==LaTeX 명령예== |
− | + | ===cases=== | |
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$$ | $$ | ||
f(n) = | f(n) = | ||
91번째 줄: | 51번째 줄: | ||
\end{cases} | \end{cases} | ||
$$ | $$ | ||
+ | ====atop==== | ||
+ | $$\tilde y=\left\{ {\ddot x\text{ if $\vec x$ odd}\atop\hat{\,\bar x+1}\text{ if even}}\right.$$ | ||
+ | |||
− | + | ===array=== | |
$$ \left\{ \begin{array}{c} a_1x+b_1y+c_1z=d_1 \\ a_2x+b_2y+c_2z=d_2 \\ a_3x+b_3y+c_3z=d_3 \end{array} \right. $$ | $$ \left\{ \begin{array}{c} a_1x+b_1y+c_1z=d_1 \\ a_2x+b_2y+c_2z=d_2 \\ a_3x+b_3y+c_3z=d_3 \end{array} \right. $$ | ||
+ | $$ \begin{array}{c|lcr} n & \text{Left} & \text{Center} & \text{Right} \\ \hline 1 & 0.24 & 1 & 125 \\ 2 & -1 & 189 & -8 \\ 3 & -20 & 2000 & 1+10i \\ \end{array} $$ | ||
+ | :<math>A=\left( \begin{array}{c.cccc}&1&2&\cdots&n\\ 1&a_{11}&a_{12}&\cdots&a_{1n}\\ 2&a_{21}&a_{22}&\cdots&a_{2n}\\ \vdots&\vdots&\vdots&\ddots&\vdots\\ n&a_{n1}&a_{n2}&\cdots&a_{nn}\end{array}\right)</math> | ||
− | + | ||
− | $$ \begin{ | + | ===eqnarray=== |
+ | $$\left.\begin{eqnarray} x+y+z&=&3\\2y&=&x+z\\2x+y&=&z\end{eqnarray}\right\}$$ | ||
− | + | ===align=== | |
:<math> | :<math> | ||
\begin{align} | \begin{align} | ||
129번째 줄: | 95번째 줄: | ||
− | + | ===underbrace=== | |
:<math>\underbrace{i \hbar \frac{\partial}{\partial t} |\varphi_\pm\rangle = \left( \frac{( \mathbf{p} -e \mathbf A)^2}{2 m} + e \phi \right) \hat 1 \mathbf |\varphi_\pm\rangle }_\mathrm{Schr\ddot{o}dinger~equation} - \underbrace{\frac{e \hbar}{2m}\mathbf{\sigma} \cdot \mathbf B \mathbf |\varphi_\pm\rangle }_\text{Stern Gerlach term}</math> | :<math>\underbrace{i \hbar \frac{\partial}{\partial t} |\varphi_\pm\rangle = \left( \frac{( \mathbf{p} -e \mathbf A)^2}{2 m} + e \phi \right) \hat 1 \mathbf |\varphi_\pm\rangle }_\mathrm{Schr\ddot{o}dinger~equation} - \underbrace{\frac{e \hbar}{2m}\mathbf{\sigma} \cdot \mathbf B \mathbf |\varphi_\pm\rangle }_\text{Stern Gerlach term}</math> | ||
[[파울리 방정식]] | [[파울리 방정식]] | ||
− | + | ===substack=== | |
$$ | $$ | ||
\sum_{ | \sum_{ | ||
143번째 줄: | 109번째 줄: | ||
$$ | $$ | ||
− | == | + | |
− | $\alpha \beta \gamma \delta \epsilon (\varepsilon) \zeta \eta \theta | + | ===크기=== |
+ | ;large | ||
+ | $$ | ||
+ | \large f^\prime(x)\ = \lim_{\Delta x\to0}\frac{f(x+\Delta x)-f(x)}{\Delta x} | ||
+ | $$ | ||
+ | ;Large | ||
+ | $$ | ||
+ | \Large f^\prime(x)\ = \lim_{\Delta x\to0}\frac{f(x+\Delta x)-f(x)}{\Delta x} | ||
+ | $$ | ||
+ | ;LARGE | ||
+ | $$ | ||
+ | \LARGE f^\prime(x)\ = \lim_{\Delta x\to0}\frac{f(x+\Delta x)-f(x)}{\Delta x} | ||
+ | $$ | ||
+ | |||
+ | |||
+ | ===그리스 문자=== | ||
+ | $$\alpha \beta \gamma \delta \epsilon (\varepsilon) \zeta \eta \theta | ||
(\vartheta) \iota \kappa \lambda \mu \nu \xi o \pi \rho \sigma \tau \upsilon | (\vartheta) \iota \kappa \lambda \mu \nu \xi o \pi \rho \sigma \tau \upsilon | ||
− | \phi (\varphi) \chi \psi \omega$ | + | \phi (\varphi) \chi \psi \omega$$ |
− | $A B \Gamma \Delta E Z H \Theta I K \Lambda M N \Xi O \Pi P \Sigma T \Upsilon | + | $$A B \Gamma \Delta E Z H \Theta I K \Lambda M N \Xi O \Pi P \Sigma T \Upsilon |
− | \Phi X \Psi \Omega$ | + | \Phi X \Psi \Omega$$ |
+ | ===글꼴=== | ||
$$\text{mathcal }\mathcal{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ | $$\text{mathcal }\mathcal{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ | ||
$$\text{mathscr }\mathscr{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ | $$\text{mathscr }\mathscr{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ | ||
159번째 줄: | 142번째 줄: | ||
$$\text{mathfrak }\mathfrak{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ | $$\text{mathfrak }\mathfrak{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ | ||
$$\text{mathfrak }\mathfrak{abcdefghijklmnopqrstuvwxyz}$$ | $$\text{mathfrak }\mathfrak{abcdefghijklmnopqrstuvwxyz}$$ | ||
+ | |||
+ | |||
+ | ===기타=== | ||
+ | * <math>\chi(t)=\left(\frac{t}{p}\right)</math> | ||
+ | * <math>\operatorname{Re} a > 0 </math> | ||
+ | * <math>x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</math> | ||
+ | * <math>720\div12=60</math> | ||
+ | * $\exists c \in (a,b) \quad \mathbf{s.t.} \quad f'(c)=\frac{f(b)-f(a)}{b-a}$ | ||
+ | * <math>\mathcal{H}om</math> | ||
+ | * <math>G\"odel</math> http://www.phil.cam.ac.uk/teaching_staff/Smith/LaTeX/other-macros/godelcorners.html | ||
+ | * <math>\Large\begin{array}{rccclBCB} &f&\longr[75]^{\alpha:{\normalsize f\rightar~g}}&g\\ \large\gamma&\longd[50]&&\longd[50]&\large\gamma\\ &u&\longr[75]_\beta&v\end{array}</math> | ||
+ | # \Large\begin{array}{rccclBCB} &f&\longr[75]^{\alpha:{\normalsize f\rightar~g}}&g\\ \large\gamma&\longd[50]&&\longd[50]&\large\gamma\\ &u&\longr[75]_\beta&v\end{array} | ||
+ | * <math>\Large\overbrace{a,...,a}^{\text{k a^,s}}, \underbrace{b,...,b}_{\text{l b^,s}}\hspace{10} \large\underbrace{\overbrace{a...a}^{\text{k a^,s}}, \overbrace{b...b}^{\text{l b^,s}}}_{\text{k+l elements}}</math> | ||
+ | # \Large\overbrace{a,...,a}^{\text{k a^,s}}, \underbrace{b,...,b}_{\text{l b^,s}}\hspace{10} \large\underbrace{\overbrace{a...a}^{\text{k a^,s}}, \overbrace{b...b}^{\text{l b^,s}}}_{\text{k+l elements}} | ||
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== 관련된 항목들 == | == 관련된 항목들 == | ||
166번째 줄: | 165번째 줄: | ||
* [[행렬과 연립방정식의 수식표현]] | * [[행렬과 연립방정식의 수식표현]] | ||
* [[화살표 모음]] | * [[화살표 모음]] | ||
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[[분류:수식표현]] | [[분류:수식표현]] |
2013년 11월 10일 (일) 04:44 판
웹과 수식표현
HTML 수식표현
웹상에서의 LaTeX을 통한 수식표현
- 구글 문서에서도 수식표현이 가능
- Google Docs Has an Equation Editor
- Google Operating System, 2009-9-17
- Google Docs Has an Equation Editor
- SITMO
- http://www.sitmo.com/latex/
- 구글이나 스프링노트와는 달리 계정없이 수식이미지를 얻을 수 있음
- 위키피디아
- Wiki의 관련항목에 가서 edit 를 누른뒤, \(\) 태그 사이에 LaTeX 명령을 써서, preview로 이미지를 얻기
- MimeTeX
- MathJax
LaTeX 명령어 입문
- 특정한 수식표현을 배우는 하나의 방법은 Wikipedia를 이용하는 것
- Wiki의 관련항목에 가서 edit 를 눌러보면, TeX 명령들을 카피해서 사용가능. 예)오일러상수 편집모드
- LaTeX 관련 페이지
- http://en.wikibooks.org/wiki/LaTeX
모르는 명령어 그림으로 알아내기
LaTeX으로 노트하기
LaTeX 명령예
cases
$$ f(n) = \begin{cases} n/2, & \text{if $n$ is even}\\ 3n+1, & \text{if $n$ is odd} \\ \end{cases} $$
atop
$$\tilde y=\left\{ {\ddot x\text{ if $\vec x$ odd}\atop\hat{\,\bar x+1}\text{ if even}}\right.$$
array
$$ \left\{ \begin{array}{c} a_1x+b_1y+c_1z=d_1 \\ a_2x+b_2y+c_2z=d_2 \\ a_3x+b_3y+c_3z=d_3 \end{array} \right. $$ $$ \begin{array}{c|lcr} n & \text{Left} & \text{Center} & \text{Right} \\ \hline 1 & 0.24 & 1 & 125 \\ 2 & -1 & 189 & -8 \\ 3 & -20 & 2000 & 1+10i \\ \end{array} $$
\[A=\left( \begin{array}{c.cccc}&1&2&\cdots&n\\ 1&a_{11}&a_{12}&\cdots&a_{1n}\\ 2&a_{21}&a_{22}&\cdots&a_{2n}\\ \vdots&\vdots&\vdots&\ddots&\vdots\\ n&a_{n1}&a_{n2}&\cdots&a_{nn}\end{array}\right)\]
eqnarray
$$\left.\begin{eqnarray} x+y+z&=&3\\2y&=&x+z\\2x+y&=&z\end{eqnarray}\right\}$$
align
\[ \begin{align} & {} \quad \int Y_{l_1}^{m_1}(\theta,\varphi)Y_{l_2}^{m_2}(\theta,\varphi)Y_{l_3}^{m_3}(\theta,\varphi)\,\sin\theta\,\mathrm{d}\theta\,\mathrm{d}\varphi \\ & = \sqrt{\frac{(2l_1+1)(2l_2+1)(2l_3+1)}{4\pi}} \begin{pmatrix} l_1 & l_2 & l_3 \\[8pt] 0 & 0 & 0 \end{pmatrix} \begin{pmatrix} l_1 & l_2 & l_3\\ m_1 & m_2 & m_3 \end{pmatrix} \end{align} \]
\[ \begin{align} \omega_{n} & =\int\cdots\int_{x_1^2+\cdots+x_n^2\leq\ 1} dx_{1}\cdots dx_{n} \\ & = \int_{-1}^{1}\left(\int\cdots \int_{x_1^2+\cdots +x_{n-1}^2\leq\ 1-x_{n}^2} dx_{1}\cdots dx_{n-1}\right)dx_{n} \end{align} \]
underbrace
\[\underbrace{i \hbar \frac{\partial}{\partial t} |\varphi_\pm\rangle = \left( \frac{( \mathbf{p} -e \mathbf A)^2}{2 m} + e \phi \right) \hat 1 \mathbf |\varphi_\pm\rangle }_\mathrm{Schr\ddot{o}dinger~equation} - \underbrace{\frac{e \hbar}{2m}\mathbf{\sigma} \cdot \mathbf B \mathbf |\varphi_\pm\rangle }_\text{Stern Gerlach term}\] 파울리 방정식
substack
$$ \sum_{ \substack{ r,s,t\geq 0 \\ r+s=m,s+t=n}} \frac{q^{rt}}{(q)_r(q)_s(q)_t}=\frac{1}{(q)_{m}(q)_{n}} $$
크기
- large
$$ \large f^\prime(x)\ = \lim_{\Delta x\to0}\frac{f(x+\Delta x)-f(x)}{\Delta x} $$
- Large
$$ \Large f^\prime(x)\ = \lim_{\Delta x\to0}\frac{f(x+\Delta x)-f(x)}{\Delta x} $$
- LARGE
$$ \LARGE f^\prime(x)\ = \lim_{\Delta x\to0}\frac{f(x+\Delta x)-f(x)}{\Delta x} $$
그리스 문자
$$\alpha \beta \gamma \delta \epsilon (\varepsilon) \zeta \eta \theta (\vartheta) \iota \kappa \lambda \mu \nu \xi o \pi \rho \sigma \tau \upsilon \phi (\varphi) \chi \psi \omega$$
$$A B \Gamma \Delta E Z H \Theta I K \Lambda M N \Xi O \Pi P \Sigma T \Upsilon \Phi X \Psi \Omega$$
글꼴
$$\text{mathcal }\mathcal{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ $$\text{mathscr }\mathscr{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ $$\text{mathbb }\mathbb{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ $$\text{mathbf }\mathbf{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ $$\text{mathbf }\mathbf{abcdefghijklmnopqrstuvwxyz}$$ $$\text{mathfrak }\mathfrak{ABCDEFGHIJKLMNOPQRSTUVWXYZ}$$ $$\text{mathfrak }\mathfrak{abcdefghijklmnopqrstuvwxyz}$$
기타
- \(\chi(t)=\left(\frac{t}{p}\right)\)
- \(\operatorname{Re} a > 0 \)
- \(x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\)
- \(720\div12=60\)
- $\exists c \in (a,b) \quad \mathbf{s.t.} \quad f'(c)=\frac{f(b)-f(a)}{b-a}$
- \(\mathcal{H}om\)
- \(G\"odel\) http://www.phil.cam.ac.uk/teaching_staff/Smith/LaTeX/other-macros/godelcorners.html
- \(\Large\begin{array}{rccclBCB} &f&\longr[75]^{\alpha:{\normalsize f\rightar~g}}&g\\ \large\gamma&\longd[50]&&\longd[50]&\large\gamma\\ &u&\longr[75]_\beta&v\end{array}\)
- \Large\begin{array}{rccclBCB} &f&\longr[75]^{\alpha:{\normalsize f\rightar~g}}&g\\ \large\gamma&\longd[50]&&\longd[50]&\large\gamma\\ &u&\longr[75]_\beta&v\end{array}
- \(\Large\overbrace{a,...,a}^{\text{k a^,s}}, \underbrace{b,...,b}_{\text{l b^,s}}\hspace{10} \large\underbrace{\overbrace{a...a}^{\text{k a^,s}}, \overbrace{b...b}^{\text{l b^,s}}}_{\text{k+l elements}}\)
- \Large\overbrace{a,...,a}^{\text{k a^,s}}, \underbrace{b,...,b}_{\text{l b^,s}}\hspace{10} \large\underbrace{\overbrace{a...a}^{\text{k a^,s}}, \overbrace{b...b}^{\text{l b^,s}}}_{\text{k+l elements}}