"Smyth formula for Mahler measures"의 두 판 사이의 차이

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imported>Pythagoras0
imported>Pythagoras0
2번째 줄: 2번째 줄:
 
;thm '''[Smyth1981]'''
 
;thm '''[Smyth1981]'''
 
$$
 
$$
m(1+x_1+x_2)=L_{-3}'(-1)=\frac{3\sqrt{3}}{4\pi}L_{-3}(2)=0.3230659472\cdots \label{Smyth1}
+
m(1+x_1+x_2)=L_{-3}'(-1)=\frac{3\sqrt{3}}{4\pi}L(\chi_{-3},2)=0.3230659472\cdots \label{Smyth1}
 
$$
 
$$
 
+
where
 +
$$L(\chi_{-3},s)=\sum_{n=1}^{\infty}\frac{\chi_{-3}(n)}{n^s}=\frac{1}{1^s}-\frac{1}{2^s}+\frac{1}{4^s}-\frac{1}{5^s}+\cdots$$
 
$$
 
$$
 
m(1+x_1+x_2+x_3)=14\zeta'(-2)=\frac{7}{2\pi^2}\zeta(3)=0.4262783988\cdots
 
m(1+x_1+x_2+x_3)=14\zeta'(-2)=\frac{7}{2\pi^2}\zeta(3)=0.4262783988\cdots
 
$$
 
$$
 
  
 
==two proofs of \ref{Smyth1}==
 
==two proofs of \ref{Smyth1}==

2015년 2월 1일 (일) 18:15 판

introduction

thm [Smyth1981]

$$ m(1+x_1+x_2)=L_{-3}'(-1)=\frac{3\sqrt{3}}{4\pi}L(\chi_{-3},2)=0.3230659472\cdots \label{Smyth1} $$ where $$L(\chi_{-3},s)=\sum_{n=1}^{\infty}\frac{\chi_{-3}(n)}{n^s}=\frac{1}{1^s}-\frac{1}{2^s}+\frac{1}{4^s}-\frac{1}{5^s}+\cdots$$ $$ m(1+x_1+x_2+x_3)=14\zeta'(-2)=\frac{7}{2\pi^2}\zeta(3)=0.4262783988\cdots $$

two proofs of \ref{Smyth1}

  • direct calculation
  • using regulator


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