라마누잔과 파이

간단한 소개

\[\frac{1}{\pi} = \frac{2 \sqrt 2}{9801} \sum_{k=0}^\infty \frac{(4k)!(1103+26390k)}{(k!)^4 396^{4k}}\!\]

 

 

\[\frac{426880 \sqrt{10005}}{\pi} = \sum_{k=0}^\infty \frac{(6k)! (13591409 + 545140134k)}{(3k)!(k!)^3 (-640320)^{3k}}\!\]

 

 

 

 

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관련된 다른 주제들

• AGM과 파이값의 계산

 

관련도서 및 추천도서

• Pi and the AGM
  
  • Jonathan M. Borwein, Peter B. Borwein
• 도서내검색
  
  • http://books.google.com/books?q=
  • http://book.daum.net/search/contentSearch.do?query=
• 도서검색
  
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참고할만한 자료

• Ramanujan, Modular Equations, and Approximations to Pi or How to Compute One Billion Digits of Pi
  
  • J. M. Borwein, P. B. Borwein and D. H. Bailey
  • The American Mathematical Monthly, Vol. 96, No. 3 (Mar., 1989), pp. 201-219
• Modular equations and approximations to Pi
  
  • S. Ramanujan
  • Quart. J. Pure Appl. Math., (1914), vol. 45, p. 350-372
• Approximations and complex multiplication according to Ramanujan
  
  • D. V. Chudnovsky and G. V. Chudnovsky,
  • Ramanujan Revisited, Academic Press Inc., Boston, (1988), p. 375-396 & p. 468-472.
• http://ko.wikipedia.org/wiki/
• http://en.wikipedia.org/wiki/
• http://front.math.ucdavis.edu/search?a=&t=&c=&n=40&s=Listings&q=
• http://www.ams.org/mathscinet/search/publications.html?pg4=AUCN&s4=&co4=AND&pg5=TI&s5=&co5=AND&pg6=PC&s6=&co6=AND&pg7=ALLF&co7=AND&Submit=Search&dr=all&yrop=eq&arg3=&yearRangeFirst=&yearRangeSecond=&pg8=ET&s8=All&s7=
• 다음백과사전 http://enc.daum.net/dic100/search.do?q=

 

 

관련기사

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블로그

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이미지 검색

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동영상

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