Differential Galois theory
imported>Pythagoras0님의 2015년 3월 2일 (월) 17:40 판 (→articles)
introduction
- differential galois theory
- Liouville
- 2008년 12월 9일 MCF 'differential Galois theory'
historical origin
- integration in finite terms
- quadrature of second order differential equation (Fuchsian differential equation)
solution by quadrature
- 일계 선형미분방정식
\(\frac{dy}{dx}+a(x)y=b(x)\)
\(y(x)e^{\int a(x)\,dx}=\int b(x)e^{\int a(x)\,dx} \,dx+C\) - \(y''-2xy'=0\)
\(y=\int e^{x^2}\, dx\) - note that the integral of an exponential naturally shows up in expression solutions
differential field
- a pair \((F,\partial)\) such that
- \(\partial(a+b)=\partial a+\partial b\)
- \(\partial(ab)=(\partial a)b+a(\partial b)\)
- \(C_F=\ker \partial\)
solvable by quadratures
- basic functions : basic elementary functions
- allowed operatrions : compositions, arithmetic operations, differentiation, integration
- examples
- an elliptic integral is representable by quadrature
elementary extension
- it is allowed to take exponentials and logarithms to make a field extension
- elementary element
- difference between Liouville extension
- exponential+ integral <=> differentiation + exponential of integral
- in elementary extension, we are not allowed to get an integrated element
Liouville extension
- an element is said to be representable by a generalized quadrature
- we can capture these properties using the concept of Liouville extension
- to get a Liouville extension, we can adjoin
- integrals
- exponentials of integrals
- algebraic extension (generalized Liouville extension)
- from these we can include the following operations
- exponential
- logarithm
- from these we can include the following operations
- For\(K_{i}=K_{i-1}(e_i)\) , one of the following condition holds
- \(e_i'\in K_{i-1}\), i.e. \(e_i=\int e_i'\in K_i\)
- \(e_{i}'/e_{i}\in K_{i-1}\) i.e. \((\log e_i)' \in K_{i-1}\)
- \(e_{i}\) is algebraic over \(K_{i-1}\)
- \(e_i'\in K_{i-1}\), i.e. \(e_i=\int e_i'\in K_i\)
- remark on exponentiation
- Let \(a,a'\in F\). Is \(b=e^a\in K\) where K is a Liouville extension?
- \(b'=a' e^a=a'b\) implies \(a'=\frac{b'}{b}\in F\).
- the exponential of the integral of a' i.e. \(e^{\int a'}=e^a+c\) must be in the Liouville extension. So \(b=e^a\in K\).
- Let \(a,a'\in F\). Is \(b=e^a\in K\) where K is a Liouville extension?
- remark on logarithm
- \(b=\log a\) is the integral of \(a'/a\in F\). So \(b\in K\)
- \(b=\log a\) is the integral of \(a'/a\in F\). So \(b\in K\)
- a few result
- K/F is a Liouville extension iff the differential Galois group K over F is solvable.
- K/F is a generalized Liouville extension iff the differential Galois group K over F has the solvable component of the identity
- K/F is a Liouville extension iff the differential Galois group K over F is solvable.
Picard-Vessiot extension
- framework for linear differential equation
- field extension is made by including solutions of DE to the base field (e.g. rational function field)
- consider monic differential equations over a differential field F
\(\mathcal{L}[Y]=Y^{(n)}+a_{n-1}Y^{(n-1)}+\cdots+a_{1}Y^{(1)}+a_0\), \(a_i\in F\) - \((E,\partial_E)\supseteq (F,\partial_F)\) is a Picard-Vessiot extension for \(\mathcal{L}\) if
- E/F is generated by n linear independent solution to \(\mathcal{L}\), i.e. adjoining basis of \(V=\mathcal{L}^{-1}(0)\) to F
- \(C_E=C_F\), \(\partial_E\mid_F=\partial_F\)
- this corresponds to the concept of the splitting fields(or Galois extensions)
- examples
- algebraic extension
- adjoining an integral
- adjoining the exponential of an integral
- we can define a Galois group for a linear differential equation
\(\operatorname{Gal}(E/F)=\{\sigma\in\operatorname{Aut}E|\partial(\sigma(n))=\sigma(\partial a), \sigma\mid _F=\operatorname{id} \}\)
- the action of an element of the Galois group is determined by its action on a basis of V
theorem
If a Picard-Vessiot extension is a Liouville extension, then the Galois group of this extension is solvable.
Fuchsian differential equation
- differential equation with regular singularities
- indicial equation
\(x(x-1)+px+q=0\)
theorem
A Fuchsian linear differential equation is solvable by quadratures if and only if the monodromy group of this equation is solvable.
solution by quadrature
- Differential Galois Theory and Non-Integrability of Hamiltonian Systems
- Integrability and non-integrability in Hamiltonian mechanics
- [1]http://www.caminos.upm.es/matematicas/morales%20ruiz/libroFSB.pdf
- http://andromeda.rutgers.edu/~liguo/DARTIII/Presentations/Khovanskii.pdf
- http://www.math.purdue.edu/~agabriel/topological_galois.pdf
encyclopedia
- http://ko.wikipedia.org/wiki/
- http://en.wikipedia.org/wiki/Differential_Galois_theory
- http://en.wikipedia.org/wiki/Homotopy_lifting_property
- http://en.wikipedia.org/wiki/covering_space
- http://en.wikipedia.org/wiki/Field_extension
expositions
- Singer, M. F., and J. H. Davenport. ‘Elementary and Liouvillian Solutions of Linear Differential Equations’. In EUROCAL ’85, edited by Bob F. Caviness, 595–96. Lecture Notes in Computer Science 204. Springer Berlin Heidelberg, 1985. http://link.springer.com/chapter/10.1007/3-540-15984-3_335.
articles
- Crespo, Teresa, Zbigniew Hajto, and Elzbieta Sowa-Adamus. ‘Galois Correspondence Theorem for Picard-Vessiot Extensions’. arXiv:1502.08026 [math], 27 February 2015. http://arxiv.org/abs/1502.08026.
- Singer, Michael F. ‘Liouvillian First Integrals of Differential Equations’. Transactions of the American Mathematical Society 333, no. 2 (1 October 1992): 673–88. doi:10.2307/2154053.
books
- Group Theory and Differential Equations
- Lawrence Markus, 1960
- An introduction to differential algebra
- Irving Kaplansky
- Irving Kaplansky
- algebraic theory of differential equations
- http://gigapedia.info/1/galois_theory
- http://gigapedia.info/1/differential+galois+theory
- http://gigapedia.info/1/Kolchin
- http://gigapedia.info/1/ritt
- http://gigapedia.info/1/Galois'+dream
- http://gigapedia.info/1/differntial+algebra