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하이젠베르크 모형 - 보충 - 편집 역사
2024-03-29T09:26:48Z
이 문서의 편집 역사
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2013년 2월 25일 (월) 14:37에 Pythagoras0님의 편집
2013-02-25T14:37:40Z
<p></p>
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">2013년 2월 25일 (월) 14:37 판</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l11" >11번째 줄:</td>
<td colspan="2" class="diff-lineno">11번째 줄:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math>\langle ab|V|ba\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_b(x_1)\psi_a(x_2)\\ &=& \langle ba|V|ab\rangle</math></div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math>\langle ab|V|ba\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_b(x_1)\psi_a(x_2)\\ &=& \langle ba|V|ab\rangle</math></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>[[분류:통계물리]]</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>[[분류:통계물리]]</div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">[[분류:평형 통계물리]]</ins></div></td></tr>
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Pythagoras0
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2012년 12월 24일 (월) 23:39에 Pythagoras0님의 편집
2012-12-24T23:39:20Z
<p></p>
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">2012년 12월 24일 (월) 23:39 판</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1" >1번째 줄:</td>
<td colspan="2" class="diff-lineno">1번째 줄:</td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>[<del class="diffchange diffchange-inline">http://exactitude.tistory.com/891 앞글</del>]에서 간단히 썼던 두 양성자 주위에 존재하는 두 전자의 해밀토니안을 더 풀어서 쓰겠습니다.</div></td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>[<ins class="diffchange diffchange-inline">[하이젠베르크 모형(Heisenberg model)]</ins>]에서 간단히 썼던 두 양성자 주위에 존재하는 두 전자의 해밀토니안을 더 풀어서 쓰겠습니다.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math>H=-\frac{\hbar^2}{2m}\nabla_1^2-\frac{\hbar^2}{2m}\nabla_2^2+V_1(x_1)+V_2(x_2)+V_{12}(x_1,x_2)</math></div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math>H=-\frac{\hbar^2}{2m}\nabla_1^2-\frac{\hbar^2}{2m}\nabla_2^2+V_1(x_1)+V_2(x_2)+V_{12}(x_1,x_2)</math></div></td></tr>
</table>
Pythagoras0
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2012년 12월 23일 (일) 13:35에 Pythagoras0님의 편집
2012-12-23T13:35:31Z
<p></p>
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">2012년 12월 23일 (일) 13:35 판</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l10" >10번째 줄:</td>
<td colspan="2" class="diff-lineno">10번째 줄:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math>\langle ab|V|ba\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_b(x_1)\psi_a(x_2)\\ &=& \langle ba|V|ab\rangle</math></div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div><math>\langle ab|V|ba\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_b(x_1)\psi_a(x_2)\\ &=& \langle ba|V|ab\rangle</math></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">[[분류:통계물리]]</ins></div></td></tr>
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Pythagoras0
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Pythagoras0: 판 4개
2012-12-23T13:23:36Z
<p>판 4개</p>
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<td colspan="1" style="background-color: #fff; color: #202122; text-align: center;">← 이전 판</td>
<td colspan="1" style="background-color: #fff; color: #202122; text-align: center;">2012년 12월 23일 (일) 13:23 판</td>
</tr><tr><td colspan="2" class="diff-notice" lang="ko"><div class="mw-diff-empty">(차이 없음)</div>
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Pythagoras0
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2012년 8월 19일 (일) 06:52에 님의 편집
2012-08-19T06:52:07Z
<p></p>
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← 이전 판</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">2012년 8월 19일 (일) 06:52 판</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l7" >7번째 줄:</td>
<td colspan="2" class="diff-lineno">7번째 줄:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>다음으로, 앞글에서 I와 J에 관한 항을 더 풀어서 써보겠습니다.</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>다음으로, 앞글에서 I와 J에 관한 항을 더 풀어서 써보겠습니다.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><math>\langle ab|V|ab\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_a(x_1)\psi_b(x_2)\\ &=& \int dx_1dx_2 |\psi_a(x_1)|^2|\psi_b(x_2)|^2V(x_1,x_2)</math></div></td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><math>\langle ab|V|ab\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_a(x_1)\psi_b(x_2)\\ &=& \int dx_1dx_2 |\psi_a(x_1)|^2|\psi_b(x_2)|^2V(x_1,x_2)<ins class="diffchange diffchange-inline">\\ &=&\langle ba|V|ba\rangle</math></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div> </div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins class="diffchange diffchange-inline"><math>\langle ab|V|ba\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_b(x_1)\psi_a(x_2)\\ &=& \langle ba|V|ab\rangle</ins></math></div></td></tr>
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2010년 2월 9일 (화) 22:01에 님의 편집
2010-02-09T22:01:00Z
<p></p>
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← 이전 판</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">2010년 2월 9일 (화) 22:01 판</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1" >1번째 줄:</td>
<td colspan="2" class="diff-lineno">1번째 줄:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>[http://exactitude.tistory.com/891 앞글]에서 간단히 썼던 두 양성자 주위에 존재하는 두 전자의 해밀토니안을 더 풀어서 쓰겠습니다.</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>[http://exactitude.tistory.com/891 앞글]에서 간단히 썼던 두 양성자 주위에 존재하는 두 전자의 해밀토니안을 더 풀어서 쓰겠습니다.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><math>H=-\frac{\hbar^2}{2m}\nabla_1^2-\frac{\hbar^2}{2m}\nabla_2^2+V_1(x_1)+V_2(x_2)+V_{12}(<del class="diffchange diffchange-inline">x1</del>,<del class="diffchange diffchange-inline">x2</del>)</math></div></td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><math>H=-\frac{\hbar^2}{2m}\nabla_1^2-\frac{\hbar^2}{2m}\nabla_2^2+V_1(x_1)+V_2(x_2)+V_{12}(<ins class="diffchange diffchange-inline">x_1</ins>,<ins class="diffchange diffchange-inline">x_2</ins>)</math></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>마지막 항은 두 <del class="diffchange diffchange-inline">저</del></div></td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>마지막 항은 두 <ins class="diffchange diffchange-inline">전자의 쿨롱 상호작용이며 나머지는 각 전자가 각 양성자에 묶여 있는 해밀토니안의 합입니다.</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div> </div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins class="diffchange diffchange-inline">다음으로, 앞글에서 I와 J에 관한 항을 더 풀어서 써보겠습니다.</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div> </div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins class="diffchange diffchange-inline"><math>\langle ab|V|ab\rangle &=& \int dx_1dx_2 \psi^*_a(x_1)\psi^*_b(x_2)V(x_1,x_2)\psi_a(x_1)\psi_b(x_2)\\ &=& \int dx_1dx_2 |\psi_a(x_1)|^2|\psi_b(x_2)|^2V(x_1,x_2)</math></ins></div></td></tr>
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2010년 2월 9일 (화) 21:55에 님의 편집
2010-02-09T21:55:13Z
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<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">← 이전 판</td>
<td colspan="2" style="background-color: #fff; color: #202122; text-align: center;">2010년 2월 9일 (화) 21:55 판</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l1" >1번째 줄:</td>
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<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">[http://exactitude.tistory.com/891 앞글]에서 간단히 썼던 두 양성자 주위에 존재하는 두 전자의 해밀토니안을 더 풀어서 쓰겠습니다.</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"><math>H=-\frac{\hbar^2}{2m}\nabla_1^2-\frac{\hbar^2}{2m}\nabla_2^2+V_1(x_1)+V_2(x_2)+V_{12}(x1,x2)</math></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #202122; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">마지막 항은 두 저</ins></div></td></tr>
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2010년 2월 9일 (화) 21:49에 님의 편집
2010-02-09T21:49:43Z
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<p><b>새 문서</b></p><div></div>