"복소 이차 수체의 데데킨트 제타함수 special values"의 두 판 사이의 차이

수학노트
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1번째 줄: 1번째 줄:
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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">이 항목의 수학노트 원문주소</h5>
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==개요==
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* 복소이차수체의 [[데데킨트 제타함수]]
  
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* [[복소이차수체의 데데킨트 제테함수]]
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==<math>s=1</math> 에서의 값==
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* [[이차 수체에 대한 디리클레 class number 공식 |이차 수체에 대한 디리클레 class number 공식]]
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* <math>K=\mathbb{Q}(\sqrt{-q})</math>
  
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==개요</h5>
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===<math>q \equiv 3 \pmod{4}</math>===
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* <math>K=\mathbb{Q}(\sqrt{-q})</math>, <math>q \geq 7</math> , <math>q \equiv 3 \pmod{4}</math> 인 경우
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* <math>d_K=-q</math>
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* <math>\chi(a)=\left(\frac{a}{q}\right)</math>
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* <math>\chi(-1)=-1</math>, <math>\tau(\chi)=i\sqrt{q}</math>
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* 다음이 성립한다
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:<math>L(1,\chi)= \frac{- \pi\sqrt{q}}{q^2}\sum_{a=1}^{q-1}\left(\frac{a}{q}\right) a=\frac{\pi h_K}{\sqrt{q}}</math>
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:<math>h_K=-\sum_{a=1}^{q-1}\left(\frac{a}{q}\right)\frac{a}{q}</math>  
  
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===<math>q \equiv 1 \pmod{4}</math>===
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* <math>K=\mathbb{Q}(\sqrt{-q})</math>  , <math>q \geq 5</math> ,  <math>q \equiv 1 \pmod{4}</math> 인 경우
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* <math>d_K=-4q</math>, <math>\chi(-1)=-1</math>, <math>\tau(\chi)=2i\sqrt{q}</math>
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* 다음이 성립한다
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:<math>L(1,\chi)= -\frac{ \pi\sqrt{q}}{8q^2}\sum_{(a,4q)=1}\chi(a) a=\frac{\pi h_K}{2\sqrt{q}}</math>
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:<math>h_K=-\frac{1}{4}\sum_{(a,4q)=1}\left(\frac{a}{q}\right)\frac{a}{q}</math>
  
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<h5 style="margin: 0px; line-height: 2em;"><math>s=1</math> 에서의 값</h5>
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==<math>s=2</math> 에서의 값==
  
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* [[이차 수체에 대한 디리클레 class number 공식 |이차 수체에 대한 디리클레 class number 공식]]<br>
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* 복소이차수체 <math>K</math>에 대하여 다음이 성립한다
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*  복소이차수체의 경우<br><math>K=\mathbb{Q}(\sqrt{-q})</math>, <math>q \geq 7</math> , <math>q \equiv 3 \pmod{4}</math> 인 경우<br><math>d_K=-q</math><br><math>\chi(a)=\left(\frac{a}{q}\right)</math><br><math>\chi(-1)=-1</math>, <math>\tau(\chi)=i\sqrt{q}</math><br><math>L(1,\chi)= \frac{- \pi\sqrt{q}}{q^2}\sum_{a=1}^{q-1}\left(\frac{a}{q}\right) a=\frac{\pi h_K}{\sqrt{q}}</math><br><math>h_K=-\sum_{a=1}^{q-1}\left(\frac{a}{q}\right)\frac{a}{q}</math><br>  <br><math>K=\mathbb{Q}(\sqrt{-q})</math>  , <math>q \geq 5</math> ,  <math>q \equiv 1 \pmod{4}</math> 인 경우<br><math>d_K=-4q</math><br><math>\chi(-1)=-1</math>, <math>\tau(\chi)=2i\sqrt{q}</math><br><math>L(1,\chi)= -\frac{ \pi\sqrt{q}}{8q^2}{\sum_{(a,4q)=1}\chi(a) a=\frac{\pi h_K}{2\sqrt{q}}</math><br><math>h_K=-\frac{1}{4}\sum_{(a,4q)=1}\left(\frac{a}{q}\right)\frac{a}{q}</math><br>
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:<math>\zeta_{K}(2)=\frac{\pi^2}{6\sqrt{|d_K|}}\sum_{(a,d_k)=1} (\frac{d_K}{a})D(e^{2\pi ia/|d_k|})</math>
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* 예를 들어, <math>K=\mathbb{Q}\sqrt{-7}</math>에 대하여, 다음이 성립한다
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:<math>\zeta_{\mathbb{Q}\sqrt{-7}}(2)=\frac{\pi^2}{3\sqrt{7}}(D(e^{2\pi i/7})+D(e^{4\pi i/7})-D(e^{6\pi i/7}))</math> 여기서 <math>D(z)</math>는 [[블로흐-비그너 다이로그(Bloch-Wigner dilogarithm)]]
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* 예
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:<math>\zeta_{\mathbb{Q}\sqrt{-1}}(2)=1.50670301</math>
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:<math>\zeta_{\mathbb{Q}\sqrt{-2}}(2)=1.75141751\cdots</math>
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:<math>\zeta_{\mathbb{Q}\sqrt{-3}}(2)=\frac{\pi^2}{6\sqrt{3}}(D(e^{2\pi i/3})-D(e^{4\pi i/3}))=\frac{\pi^2}{3\sqrt{3}}D(e^{2\pi i/3})=1.285190955484149\cdots</math>
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:<math>\zeta_{\mathbb{Q}\sqrt{-7}}(2)=\frac{\pi^2}{3\sqrt{7}}(D(e^{2\pi i/7})+D(e^{4\pi i/7})-D(e^{6\pi i/7}))=1.89484145</math>
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:<math>\zeta_{\mathbb{Q}\sqrt{-11}}(2)=1.49613186</math>
  
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* http://books.google.co.kr/books?id=yrmT56mpw3kC&pg=PA367&dq=smallest+norms+of+prime+ideals&hl=ko&ei=IMRTTIaRGoqWvAP88MUZ&sa=X&oi=book_result&ct=result&resnum=4&ved=0CDgQ6AEwAw#v=onepage&q=smallest%20norms%20of%20prime%20ideals&f=false
  
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<h5 style="margin: 0px; line-height: 2em;"><math>s=2</math> 에서의 값</h5>
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* 복소이차수체의 경우<br><math>\zeta_{K}(2)=\frac{\pi^2}{6\sqrt{|d_K|}}\sum_{(a,d_k)=1} (\frac{d_K}{a})D(e^{2\pi ia/|d_k|})</math><br><math>\zeta_{\mathbb{Q}\sqrt{-7}}(2)=\frac{\pi^2}{3\sqrt{7}}(D(e^{2\pi i/7})+D(e^{4\pi i/7})-D(e^{6\pi i/7}))</math><br> 여기서 <math>D(z)</math>는 [[블로흐-비그너 다이로그(Bloch-Wigner dilogarithm)]]<br>
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===figure eight knot complement===
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*  예<br><math>\zeta_{\mathbb{Q}\sqrt{-1}}(2)=1.50670301</math><br><math>\zeta_{\mathbb{Q}\sqrt{-2}}(2)=1.75141751\cdots</math><br><math>\zeta_{\mathbb{Q}\sqrt{-3}}(2)=\frac{\pi^2}{6\sqrt{3}}(D(e^{2\pi i/3})-D(e^{4\pi i/3}))=\frac{\pi^2}{3\sqrt{3}}D(e^{2\pi i/3})=1.285190955484149\cdots</math><br><math>\zeta_{\mathbb{Q}\sqrt{-7}}(2)=\frac{\pi^2}{3\sqrt{7}}(D(e^{2\pi i/7})+D(e^{4\pi i/7})-D(e^{6\pi i/7}))=1.89484145</math><br><math>\zeta_{\mathbb{Q}\sqrt{-11}}(2)=1.49613186</math><br>
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* <math>V=\frac{9\sqrt{3}}{\pi^2}\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=3D(e^{\frac{2i\pi}{3}})=2D(e^{\frac{i\pi}{3}})=2.029883212819\cdots</math>
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* <math>\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=\frac{\pi^2}{3\sqrt{3}}D(e^{\frac{2\pi i}{3}})</math>
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* <math>L_{-3}(2)=\frac{2}{\sqrt{3}}D(e^{\frac{2\pi i}{3}})</math>
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*  2.02988321281930725
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:<math>V(4_{1})=\frac{9\sqrt{3}}{\pi^2}\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=3D(e^{\frac{2i\pi}{3}})=2D(e^{\frac{i\pi}{3}})=2.029883212819\cdots</math>
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* [[매듭이론 (knot theory)]]
  
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* http://books.google.co.kr/books?id=yrmT56mpw3kC&pg=PA367&dq=smallest+norms+of+prime+ideals&hl=ko&ei=IMRTTIaRGoqWvAP88MUZ&sa=X&oi=book_result&ct=result&resnum=4&ved=0CDgQ6AEwAw#v=onepage&q=smallest%20norms%20of%20prime%20ideals&f=false<br>
 
  
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==메모==
  
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* <math>s=1</math> 에서의 <math>L_{d_K}'(1)</math>의 값:<math>L_{d_K}'(1)=\frac{2\pi h_K(\gamma+\ln 2\pi)}{w_K \cdot \sqrt{|d_K|}}-\frac{\pi}{\sqrt{|d_K|}}\sum_{(a,d_K)=1}\chi(a)\log\Gamma (\frac{a}{|d_K|})</math>
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* [[L-함수의 미분]] 항목 참조
  
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<h5 style="line-height: 2em; margin: 0px;">figure eight knot complement</h5>
 
  
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<math>V=\frac{9\sqrt{3}}{\pi^2}\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=3D(e^{\frac{2i\pi}{3}})=2D(e^{\frac{i\pi}{3}})=2.029883212819\cdots</math>
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<math>\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=\frac{\pi^2}{3\sqrt{3}}D(e^{\frac{2\pi i}{3}})</math>
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==관련된 항목들==
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* [[이차 수체(quadratic number fields) 의 정수론]]
  
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<math>L_{-3}(2)=\frac{2}{\sqrt{3}}D(e^{\frac{2\pi  i}{3}})</math>
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==매스매티카 파일 및 계산 리소스==
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* https://docs.google.com/file/d/0B8XXo8Tve1cxc00tSVRvMXluOWM/edit
  
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*  2.02988321281930725<br><math>V(4_{1})=\frac{9\sqrt{3}}{\pi^2}\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=3D(e^{\frac{2i\pi}{3}})=2D(e^{\frac{i\pi}{3}})=2.029883212819\cdots</math><br>
 
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* [[매듭이론 (knot theory)]]<br>
 
  
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[[분류:정수론]]
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==역사</h5>
 
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* http://www.google.com/search?hl=en&tbs=tl:1&q=
 
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* [[수학사연표 (역사)|수학사연표]]
 
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==메모</h5>
 
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* <math>s=1</math> 에서의 <math>L_{d_K}'(1)</math>의 값<br><math>L_{d_K}'(1)=\frac{2\pi h_K(\gamma+\ln 2\pi)}{w_K \cdot \sqrt{|d_K|}}-\frac{\pi}{\sqrt{|d_K|}}\sum_{(a,d_K)=1}\chi(a)\log\Gamma (\frac{a}{|d_K|})</math><br>
 
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* [[L-함수의 미분]] 항목 참조<br>
 
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* Math Overflow http://mathoverflow.net/search?q=
 
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==관련된 항목들</h5>
 
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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">수학용어번역</h5>
 
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* 단어사전<br>
 
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** http://translate.google.com/#en|ko|
 
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** http://ko.wiktionary.org/wiki/
 
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* 발음사전 http://www.forvo.com/search/
 
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* [http://mathnet.kaist.ac.kr/mathnet/math_list.php?mode=list&ftype=&fstr= 대한수학회 수학 학술 용어집]<br>
 
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** http://mathnet.kaist.ac.kr/mathnet/math_list.php?mode=list&ftype=eng_term&fstr=
 
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* [http://www.kss.or.kr/pds/sec/dic.aspx 한국통계학회 통계학 용어 온라인 대조표]
 
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* [http://www.nktech.net/science/term/term_l.jsp?l_mode=cate&s_code_cd=MA 남·북한수학용어비교]
 
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* [http://kms.or.kr/home/kor/board/bulletin_list_subject.asp?bulletinid=%7BD6048897-56F9-43D7-8BB6-50B362D1243A%7D&boardname=%BC%F6%C7%D0%BF%EB%BE%EE%C5%E4%B7%D0%B9%E6&globalmenu=7&localmenu=4 대한수학회 수학용어한글화 게시판]
 
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==매스매티카 파일 및 계산 리소스</h5>
 
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*  
 
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* http://www.wolframalpha.com/input/?i=
 
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* http://functions.wolfram.com/
 
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* [http://dlmf.nist.gov/ NIST Digital Library of Mathematical Functions]
 
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* [http://people.math.sfu.ca/%7Ecbm/aands/toc.htm Abramowitz and Stegun Handbook of mathematical functions]
 
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* [http://www.research.att.com/%7Enjas/sequences/index.html The On-Line Encyclopedia of Integer Sequences]
 
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* [http://numbers.computation.free.fr/Constants/constants.html Numbers, constants and computation]
 
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* [https://docs.google.com/open?id=0B8XXo8Tve1cxMWI0NzNjYWUtNmIwZi00YzhkLTkzNzQtMDMwYmVmYmIxNmIw 매스매티카 파일 목록]
 
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==사전 형태의 자료</h5>
 
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* http://ko.wikipedia.org/wiki/
 
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* http://en.wikipedia.org/wiki/
 
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* [http://eom.springer.de/default.htm The Online Encyclopaedia of Mathematics]
 
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* [http://dlmf.nist.gov NIST Digital Library of Mathematical Functions]
 
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* [http://eqworld.ipmnet.ru/ The World of Mathematical Equations]
 
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==리뷰논문, 에세이, 강의노트</h5>
 
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==관련논문</h5>
 
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* http://www.jstor.org/action/doBasicSearch?Query=
 
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* http://www.ams.org/mathscinet
 
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* http://dx.doi.org/
 
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==관련도서</h5>
 
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*  도서내검색<br>
 
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** http://books.google.com/books?q=
 
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** http://book.daum.net/search/contentSearch.do?query=
 

2020년 11월 13일 (금) 07:27 기준 최신판

개요


\(s=1\) 에서의 값


\(q \equiv 3 \pmod{4}\)

  • \(K=\mathbb{Q}(\sqrt{-q})\), \(q \geq 7\) , \(q \equiv 3 \pmod{4}\) 인 경우
  • \(d_K=-q\)
  • \(\chi(a)=\left(\frac{a}{q}\right)\)
  • \(\chi(-1)=-1\), \(\tau(\chi)=i\sqrt{q}\)
  • 다음이 성립한다

\[L(1,\chi)= \frac{- \pi\sqrt{q}}{q^2}\sum_{a=1}^{q-1}\left(\frac{a}{q}\right) a=\frac{\pi h_K}{\sqrt{q}}\] \[h_K=-\sum_{a=1}^{q-1}\left(\frac{a}{q}\right)\frac{a}{q}\]

\(q \equiv 1 \pmod{4}\)

  • \(K=\mathbb{Q}(\sqrt{-q})\) , \(q \geq 5\) , \(q \equiv 1 \pmod{4}\) 인 경우
  • \(d_K=-4q\), \(\chi(-1)=-1\), \(\tau(\chi)=2i\sqrt{q}\)
  • 다음이 성립한다

\[L(1,\chi)= -\frac{ \pi\sqrt{q}}{8q^2}\sum_{(a,4q)=1}\chi(a) a=\frac{\pi h_K}{2\sqrt{q}}\] \[h_K=-\frac{1}{4}\sum_{(a,4q)=1}\left(\frac{a}{q}\right)\frac{a}{q}\]



\(s=2\) 에서의 값

  • 복소이차수체 \(K\)에 대하여 다음이 성립한다

\[\zeta_{K}(2)=\frac{\pi^2}{6\sqrt{|d_K|}}\sum_{(a,d_k)=1} (\frac{d_K}{a})D(e^{2\pi ia/|d_k|})\]

  • 예를 들어, \(K=\mathbb{Q}\sqrt{-7}\)에 대하여, 다음이 성립한다

\[\zeta_{\mathbb{Q}\sqrt{-7}}(2)=\frac{\pi^2}{3\sqrt{7}}(D(e^{2\pi i/7})+D(e^{4\pi i/7})-D(e^{6\pi i/7}))\] 여기서 \(D(z)\)는 블로흐-비그너 다이로그(Bloch-Wigner dilogarithm)

  • 예

\[\zeta_{\mathbb{Q}\sqrt{-1}}(2)=1.50670301\] \[\zeta_{\mathbb{Q}\sqrt{-2}}(2)=1.75141751\cdots\] \[\zeta_{\mathbb{Q}\sqrt{-3}}(2)=\frac{\pi^2}{6\sqrt{3}}(D(e^{2\pi i/3})-D(e^{4\pi i/3}))=\frac{\pi^2}{3\sqrt{3}}D(e^{2\pi i/3})=1.285190955484149\cdots\] \[\zeta_{\mathbb{Q}\sqrt{-7}}(2)=\frac{\pi^2}{3\sqrt{7}}(D(e^{2\pi i/7})+D(e^{4\pi i/7})-D(e^{6\pi i/7}))=1.89484145\] \[\zeta_{\mathbb{Q}\sqrt{-11}}(2)=1.49613186\]



figure eight knot complement

  • \(V=\frac{9\sqrt{3}}{\pi^2}\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=3D(e^{\frac{2i\pi}{3}})=2D(e^{\frac{i\pi}{3}})=2.029883212819\cdots\)
  • \(\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=\frac{\pi^2}{3\sqrt{3}}D(e^{\frac{2\pi i}{3}})\)
  • \(L_{-3}(2)=\frac{2}{\sqrt{3}}D(e^{\frac{2\pi i}{3}})\)
  • 2.02988321281930725

\[V(4_{1})=\frac{9\sqrt{3}}{\pi^2}\zeta_{\mathbb{Q}(\sqrt{-3})}(2)=3D(e^{\frac{2i\pi}{3}})=2D(e^{\frac{i\pi}{3}})=2.029883212819\cdots\]




메모

  • \(s=1\) 에서의 \(L_{d_K}'(1)\)의 값\[L_{d_K}'(1)=\frac{2\pi h_K(\gamma+\ln 2\pi)}{w_K \cdot \sqrt{|d_K|}}-\frac{\pi}{\sqrt{|d_K|}}\sum_{(a,d_K)=1}\chi(a)\log\Gamma (\frac{a}{|d_K|})\]
  • L-함수의 미분 항목 참조



관련된 항목들


매스매티카 파일 및 계산 리소스

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