"데데킨트 합"의 두 판 사이의 차이

수학노트
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<h5 style="margin: 0px; line-height: 2em;">h,k가 작은 경우 데데킨트합의 목록</h5>
 
<h5 style="margin: 0px; line-height: 2em;">h,k가 작은 경우 데데킨트합의 목록</h5>
  
* <math>s(h,k)</math><br><math>\left( \begin{array}{cccc}  s( & 1,1 & )= & 0 \\  s( & 1,2 & )= & 0 \\  s( & 1,3 & )= & \frac{1}{18} \\  s( & 2,3 & )= & -\frac{1}{18} \\  s( & 1,4 & )= & \frac{1}{8} \\  s( & 3,4 & )= & -\frac{1}{8} \\  s( & 1,5 & )= & \frac{1}{5} \\  s( & 2,5 & )= & 0 \\  s( & 3,5 & )= & 0 \\  s( & 4,5 & )= & -\frac{1}{5} \\  s( & 1,6 & )= & \frac{5}{18} \\  s( & 5,6 & )= & -\frac{5}{18} \\  s( & 1,7 & )= & \frac{5}{14} \\  s( & 2,7 & )= & \frac{1}{14} \\  s( & 3,7 & )= & -\frac{1}{14} \\  s( & 4,7 & )= & \frac{1}{14} \\  s( & 5,7 & )= & -\frac{1}{14} \\  s( & 6,7 & )= & -\frac{5}{14} \\  s( & 1,8 & )= & \frac{7}{16} \\  s( & 3,8 & )= & \frac{1}{16} \\  s( & 5,8 & )= & -\frac{1}{16} \\  s( & 7,8 & )= & -\frac{7}{16} \\  s( & 1,9 & )= & \frac{14}{27} \\  s( & 2,9 & )= & \frac{4}{27} \\  s( & 4,9 & )= & -\frac{4}{27} \\  s( & 5,9 & )= & \frac{4}{27} \\  s( & 7,9 & )= & -\frac{4}{27} \\  s( & 8,9 & )= & -\frac{14}{27} \\  s( & 1,10 & )= & \frac{3}{5} \\  s( & 3,10 & )= & 0 \\  s( & 7,10 & )= & 0 \\  s( & 9,10 & )= & -\frac{3}{5} \\  s( & 1,11 & )= & \frac{15}{22} \\  s( & 2,11 & )= & \frac{5}{22} \\  s( & 3,11 & )= & \frac{3}{22} \\  s( & 4,11 & )= & \frac{3}{22} \\  s( & 5,11 & )= & -\frac{5}{22} \\  s( & 6,11 & )= & \frac{5}{22} \\  s( & 7,11 & )= & -\frac{3}{22} \\  s( & 8,11 & )= & -\frac{3}{22} \\  s( & 9,11 & )= & -\frac{5}{22} \\  s( & 10,11 & )= & -\frac{15}{22} \\  s( & 1,12 & )= & \frac{55}{72} \\  s( & 5,12 & )= & -\frac{1}{72} \\  s( & 7,12 & )= & \frac{1}{72} \\  s( & 11,12 & )= & -\frac{55}{72} \\  s( & 1,13 & )= & \frac{11}{13} \\  s( & 2,13 & )= & \frac{4}{13} \\  s( & 3,13 & )= & \frac{1}{13} \\  s( & 4,13 & )= & -\frac{1}{13} \\  s( & 5,13 & )= & 0 \\  s( & 6,13 & )= & -\frac{4}{13} \\  s( & 7,13 & )= & \frac{4}{13} \\  s( & 8,13 & )= & 0 \\  s( & 9,13 & )= & \frac{1}{13} \\  s( & 10,13 & )= & -\frac{1}{13} \\  s( & 11,13 & )= & -\frac{4}{13} \\  s( & 12,13 & )= & -\frac{11}{13} \\  s( & 1,14 & )= & \frac{13}{14} \\  s( & 3,14 & )= & \frac{3}{14} \\  s( & 5,14 & )= & \frac{3}{14} \\  s( & 9,14 & )= & -\frac{3}{14} \\  s( & 11,14 & )= & -\frac{3}{14} \\  s( & 13,14 & )= & -\frac{13}{14} \\  s( & 1,15 & )= & \frac{91}{90} \\  s( & 2,15 & )= & \frac{7}{18} \\  s( & 4,15 & )= & \frac{19}{90} \\  s( & 7,15 & )= & -\frac{7}{18} \\  s( & 8,15 & )= & \frac{7}{18} \\  s( & 11,15 & )= & -\frac{19}{90} \\  s( & 13,15 & )= & -\frac{7}{18} \\  s( & 14,15 & )= & -\frac{91}{90} \\  s( & 1,16 & )= & \frac{35}{32} \\  s( & 3,16 & )= & \frac{5}{32} \\  s( & 5,16 & )= & -\frac{5}{32} \\  s( & 7,16 & )= & -\frac{3}{32} \\  s( & 9,16 & )= & \frac{3}{32} \\  s( & 11,16 & )= & \frac{5}{32} \\  s( & 13,16 & )= & -\frac{5}{32} \\  s( & 15,16 & )= & -\frac{35}{32} \\  s( & 1,17 & )= & \frac{20}{17} \\  s( & 2,17 & )= & \frac{8}{17} \\  s( & 3,17 & )= & \frac{5}{17} \\  s( & 4,17 & )= & 0 \\  s( & 5,17 & )= & \frac{1}{17} \\  s( & 6,17 & )= & \frac{5}{17} \\  s( & 7,17 & )= & \frac{1}{17} \\  s( & 8,17 & )= & -\frac{8}{17} \\  s( & 9,17 & )= & \frac{8}{17} \\  s( & 10,17 & )= & -\frac{1}{17} \\  s( & 11,17 & )= & -\frac{5}{17} \\  s( & 12,17 & )= & -\frac{1}{17} \\  s( & 13,17 & )= & 0 \\  s( & 14,17 & )= & -\frac{5}{17} \\  s( & 15,17 & )= & -\frac{8}{17} \\  s( & 16,17 & )= & -\frac{20}{17} \\  s( & 1,18 & )= & \frac{34}{27} \\  s( & 5,18 & )= & \frac{2}{27} \\  s( & 7,18 & )= & -\frac{2}{27} \\  s( & 11,18 & )= & \frac{2}{27} \\  s( & 13,18 & )= & -\frac{2}{27} \\  s( & 17,18 & )= & -\frac{34}{27} \\  s( & 1,19 & )= & \frac{51}{38} \\  s( & 2,19 & )= & \frac{21}{38} \\  s( & 3,19 & )= & \frac{9}{38} \\  s( & 4,19 & )= & \frac{11}{38} \\  s( & 5,19 & )= & \frac{11}{38} \\  s( & 6,19 & )= & -\frac{9}{38} \\  s( & 7,19 & )= & \frac{3}{38} \\  s( & 8,19 & )= & -\frac{3}{38} \\  s( & 9,19 & )= & -\frac{21}{38} \\  s( & 10,19 & )= & \frac{21}{38} \\  s( & 11,19 & )= & \frac{3}{38} \\  s( & 12,19 & )= & -\frac{3}{38} \\  s( & 13,19 & )= & \frac{9}{38} \\  s( & 14,19 & )= & -\frac{11}{38} \\  s( & 15,19 & )= & -\frac{11}{38} \\  s( & 16,19 & )= & -\frac{9}{38} \\  s( & 17,19 & )= & -\frac{21}{38} \\  s( & 18,19 & )= & -\frac{51}{38} \\  s( & 1,20 & )= & \frac{57}{40} \\  s( & 3,20 & )= & \frac{3}{8} \\  s( & 7,20 & )= & \frac{3}{8} \\  s( & 9,20 & )= & -\frac{7}{40} \\  s( & 11,20 & )= & \frac{7}{40} \\  s( & 13,20 & )= & -\frac{3}{8} \\  s( & 17,20 & )= & -\frac{3}{8} \\  s( & 19,20 & )= & -\frac{57}{40} \end{array} \right)</math><br>
+
* <math>s(h,k)</math><br> s(1,1)=0<br> s(1,2)=0<br> s(1,3)=1/18<br> s(2,3)=-(1/18)<br> s(1,4)=1/8<br> s(3,4)=-(1/8)<br> s(1,5)=1/5<br> s(2,5)=0<br> s(3,5)=0<br> s(4,5)=-(1/5)<br> s(1,6)=5/18<br> s(5,6)=-(5/18)<br> s(1,7)=5/14<br> s(2,7)=1/14<br> s(3,7)=-(1/14)<br> s(4,7)=1/14<br> s(5,7)=-(1/14)<br> s(6,7)=-(5/14)<br> s(1,8)=7/16<br> s(3,8)=1/16<br> s(5,8)=-(1/16)<br> s(7,8)=-(7/16)<br> s(1,9)=14/27<br> s(2,9)=4/27<br> s(4,9)=-(4/27)<br> s(5,9)=4/27<br> s(7,9)=-(4/27)<br> s(8,9)=-(14/27)<br> s(1,10)=3/5<br> s(3,10)=0<br> s(7,10)=0<br> s(9,10)=-(3/5)<br> s(1,11)=15/22<br> s(2,11)=5/22<br> s(3,11)=3/22<br> s(4,11)=3/22<br> s(5,11)=-(5/22)<br> s(6,11)=5/22<br> s(7,11)=-(3/22)<br> s(8,11)=-(3/22)<br> s(9,11)=-(5/22)<br> s(10,11)=-(15/22)<br> s(1,12)=55/72<br> s(5,12)=-(1/72)<br> s(7,12)=1/72<br> s(11,12)=-(55/72)<br> s(1,13)=11/13<br> s(2,13)=4/13<br> s(3,13)=1/13<br> s(4,13)=-(1/13)<br> s(5,13)=0<br> s(6,13)=-(4/13)<br> s(7,13)=4/13<br> s(8,13)=0<br> s(9,13)=1/13<br> s(10,13)=-(1/13)<br> s(11,13)=-(4/13)<br> s(12,13)=-(11/13)<br> s(1,14)=13/14<br> s(3,14)=3/14<br> s(5,14)=3/14<br> s(9,14)=-(3/14)<br> s(11,14)=-(3/14)<br> s(13,14)=-(13/14)<br> s(1,15)=91/90<br> s(2,15)=7/18<br> s(4,15)=19/90<br> s(7,15)=-(7/18)<br> s(8,15)=7/18<br> s(11,15)=-(19/90)<br> s(13,15)=-(7/18)<br> s(14,15)=-(91/90)<br> s(1,16)=35/32<br> s(3,16)=5/32<br> s(5,16)=-(5/32)<br> s(7,16)=-(3/32)<br> s(9,16)=3/32<br> s(11,16)=5/32<br> s(13,16)=-(5/32)<br> s(15,16)=-(35/32)<br> s(1,17)=20/17<br> s(2,17)=8/17<br> s(3,17)=5/17<br> s(4,17)=0<br> s(5,17)=1/17<br> s(6,17)=5/17<br> s(7,17)=1/17<br> s(8,17)=-(8/17)<br> s(9,17)=8/17<br> s(10,17)=-(1/17)<br> s(11,17)=-(5/17)<br> s(12,17)=-(1/17)<br> s(13,17)=0<br> s(14,17)=-(5/17)<br> s(15,17)=-(8/17)<br> s(16,17)=-(20/17)<br> s(1,18)=34/27<br> s(5,18)=2/27<br> s(7,18)=-(2/27)<br> s(11,18)=2/27<br> s(13,18)=-(2/27)<br> s(17,18)=-(34/27)<br> s(1,19)=51/38<br> s(2,19)=21/38<br> s(3,19)=9/38<br> s(4,19)=11/38<br> s(5,19)=11/38<br> s(6,19)=-(9/38)<br> s(7,19)=3/38<br> s(8,19)=-(3/38)<br> s(9,19)=-(21/38)<br> s(10,19)=21/38<br> s(11,19)=3/38<br> s(12,19)=-(3/38)<br> s(13,19)=9/38<br> s(14,19)=-(11/38)<br> s(15,19)=-(11/38)<br> s(16,19)=-(9/38)<br> s(17,19)=-(21/38)<br> s(18,19)=-(51/38)<br> s(1,20)=57/40<br> s(3,20)=3/8<br> s(7,20)=3/8<br> s(9,20)=-(7/40)<br> s(11,20)=7/40<br> s(13,20)=-(3/8)<br> s(17,20)=-(3/8)<br> s(19,20)=-(57/40)<br>
 
 
 
 
  
 
 
 
 

2010년 1월 14일 (목) 01:08 판

이 항목의 스프링노트 원문주소

 

 

 

개요

 

 

정의
  • 다음과 같이 sawtooth 함수를 정의하자
    \(\left((x)\right)= \begin{cases} x-\lfloor x\rfloor - 1/2 & \mbox{ if }x\in\mathbb{R}\setminus\mathbb{Z} \\ 0 & \mbox{ if } x\in\mathbb{Z} \end{cases}\)
    \(\lfloor x\rfloor\)는 \(x\)이하의 최대정수함수(가우스함수)

  • \(((0.8))=0.8-0-0.5=0.3\)
    \(((-0.2))=-0.2-(-1)-0.5=0.3\)
  • 서로 소인 두 정수\(h, k\,(k>0)\)에 대하여 데데킨트 합 \(s(h,k)\)은 다음과 같이 정의됨
    \(s(h,k)=\sum_{n\mod k} \left( \left( \frac{n}{k} \right) \right) \left( \left( \frac{hn}{k} \right) \right)\)
    \(s(h,k)=\sum_{n=1}^{k-1} \frac{n}{k} \left( \left( \frac{hn}{k} \right) \right)\)
     

 

 

코탄젠트합으로서의 표현
  • 서로 소인 두 정수\(b,c\,(c>0)\)에 대하여 다음 등식이 성립함
    \(s(b,c)=\frac{1}{4c}\sum_{n=1}^{c-1} \cot \left( \frac{\pi n}{c} \right) \cot \left( \frac{\pi nb}{c} \right)\)

 

 

상호법칙
  • (정리) 데데킨트
    서로 소인 양의 정수 \(d\)와 \(c\)에 대하여 다음이 성립한다.
    \(s(d,c)+s(c,d) =\frac{1}{12}\left(\frac{d}{c}+\frac{1}{dc}+\frac{c}{d}\right)-\frac{1}{4}\)

 

(증명)

\(F(z)=\cot \pi z\, \cot \pi cz\, \cot \pi dz\)

사각형 \(\pm iM, 1+\pm iM\) 을 조금 수정하여 0은 포함하고, 1은 빠지도록 하는 컨투어 \(\Gamma\)에 대한 적분을 사용한다.

\(\lim_{M\to \infty}\cot (x+iM)=-i\)이므로, \(\lim_{M\to \infty}F(x+iM)=-i\) 임을 확인하자.

\(\int_{\Gamma}F(z)dz\) 는 \(M\)에 의존하지 않으므로, \(\int_{\Gamma}F(z)dz = \lim_{M\to\infty}\int_{\Gamma}F(z)dz=-2i\)을 얻는다.

따라서 \(\Gamma\) 내부에 있는 유수의 합 \(S\)는 \(-\frac{1}{\pi}\) 가 된다.

 

폴은 다음과 같은 점에서 발생한다.

  • \(z=0\)
  • \(z=\lambda/c\,, \lambda=1,2,\cdots, c-1\)
  • \(z=\mu/d\,, \mu=1,2,\cdots, d-1\)

\(z=\lambda/c\) 에서의 유수는 \(\frac{1}{\pi c}\cot \frac{\pi \lambda}{c}\cot\frac{\pi d\lambda}{c}\)

\(z=\mu/c\) 에서의 유수는 \(\frac{1}{\pi d}\cot \frac{\pi \mu}{c}\cot\frac{\pi d\mu}{c}\)

 

 코탄젠트의 급수전개를 사용하여 \(z=0\)에서의 유수를 구하자.

\(F(z)=\cot \pi z\, \cot \pi cz\, \cot \pi dz =\frac{1}{\pi^3 cd z^3}(1-\frac{\pi^2z^2}{3}-\cdots)(1-\frac{\pi^2z^2d^2}{3}-\cdots)(1-\frac{\pi^2z^2c^2}{3}-\cdots)\)

따라서 \(z=0\)에서의 유수는 \(-\frac{1}{3\pi}\left(\frac{d}{c}+\frac{1}{cd}+\frac{c}{d}\right)\) 이다. 

 

\(S=\frac{4}{\pi}[-\frac{1}{12}\left(\frac{d}{c}+\frac{1}{dc}+\frac{c}{d}\right)+s(d,c)+s(c,d)]=-\frac{1}{\pi}\) 를 얻는다. ■

 

 

일반화

\(D(a,b;c)=\sum_{n\mod c} \left( \left( \frac{an}{c} \right) \right) \left( \left( \frac{bn}{c} \right) \right)\)

 

 

h,k가 작은 경우 데데킨트합의 목록
  • \(s(h,k)\)
    s(1,1)=0
    s(1,2)=0
    s(1,3)=1/18
    s(2,3)=-(1/18)
    s(1,4)=1/8
    s(3,4)=-(1/8)
    s(1,5)=1/5
    s(2,5)=0
    s(3,5)=0
    s(4,5)=-(1/5)
    s(1,6)=5/18
    s(5,6)=-(5/18)
    s(1,7)=5/14
    s(2,7)=1/14
    s(3,7)=-(1/14)
    s(4,7)=1/14
    s(5,7)=-(1/14)
    s(6,7)=-(5/14)
    s(1,8)=7/16
    s(3,8)=1/16
    s(5,8)=-(1/16)
    s(7,8)=-(7/16)
    s(1,9)=14/27
    s(2,9)=4/27
    s(4,9)=-(4/27)
    s(5,9)=4/27
    s(7,9)=-(4/27)
    s(8,9)=-(14/27)
    s(1,10)=3/5
    s(3,10)=0
    s(7,10)=0
    s(9,10)=-(3/5)
    s(1,11)=15/22
    s(2,11)=5/22
    s(3,11)=3/22
    s(4,11)=3/22
    s(5,11)=-(5/22)
    s(6,11)=5/22
    s(7,11)=-(3/22)
    s(8,11)=-(3/22)
    s(9,11)=-(5/22)
    s(10,11)=-(15/22)
    s(1,12)=55/72
    s(5,12)=-(1/72)
    s(7,12)=1/72
    s(11,12)=-(55/72)
    s(1,13)=11/13
    s(2,13)=4/13
    s(3,13)=1/13
    s(4,13)=-(1/13)
    s(5,13)=0
    s(6,13)=-(4/13)
    s(7,13)=4/13
    s(8,13)=0
    s(9,13)=1/13
    s(10,13)=-(1/13)
    s(11,13)=-(4/13)
    s(12,13)=-(11/13)
    s(1,14)=13/14
    s(3,14)=3/14
    s(5,14)=3/14
    s(9,14)=-(3/14)
    s(11,14)=-(3/14)
    s(13,14)=-(13/14)
    s(1,15)=91/90
    s(2,15)=7/18
    s(4,15)=19/90
    s(7,15)=-(7/18)
    s(8,15)=7/18
    s(11,15)=-(19/90)
    s(13,15)=-(7/18)
    s(14,15)=-(91/90)
    s(1,16)=35/32
    s(3,16)=5/32
    s(5,16)=-(5/32)
    s(7,16)=-(3/32)
    s(9,16)=3/32
    s(11,16)=5/32
    s(13,16)=-(5/32)
    s(15,16)=-(35/32)
    s(1,17)=20/17
    s(2,17)=8/17
    s(3,17)=5/17
    s(4,17)=0
    s(5,17)=1/17
    s(6,17)=5/17
    s(7,17)=1/17
    s(8,17)=-(8/17)
    s(9,17)=8/17
    s(10,17)=-(1/17)
    s(11,17)=-(5/17)
    s(12,17)=-(1/17)
    s(13,17)=0
    s(14,17)=-(5/17)
    s(15,17)=-(8/17)
    s(16,17)=-(20/17)
    s(1,18)=34/27
    s(5,18)=2/27
    s(7,18)=-(2/27)
    s(11,18)=2/27
    s(13,18)=-(2/27)
    s(17,18)=-(34/27)
    s(1,19)=51/38
    s(2,19)=21/38
    s(3,19)=9/38
    s(4,19)=11/38
    s(5,19)=11/38
    s(6,19)=-(9/38)
    s(7,19)=3/38
    s(8,19)=-(3/38)
    s(9,19)=-(21/38)
    s(10,19)=21/38
    s(11,19)=3/38
    s(12,19)=-(3/38)
    s(13,19)=9/38
    s(14,19)=-(11/38)
    s(15,19)=-(11/38)
    s(16,19)=-(9/38)
    s(17,19)=-(21/38)
    s(18,19)=-(51/38)
    s(1,20)=57/40
    s(3,20)=3/8
    s(7,20)=3/8
    s(9,20)=-(7/40)
    s(11,20)=7/40
    s(13,20)=-(3/8)
    s(17,20)=-(3/8)
    s(19,20)=-(57/40)

 

재미있는 사실

 

 

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