"타원곡선 y²=x³-x"의 두 판 사이의 차이

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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">이 항목의 스프링노트 원문주소</h5>
  
 
 
 
 
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<h5 style="line-height: 3.428em; margin-top: 0px; margin-right: 0px; margin-bottom: 0px; margin-left: 0px; color: rgb(34, 61, 103); font-family: 'malgun gothic', dotum, gulim, sans-serif; font-size: 1.166em; background-image: ; background-color: initial; background-position: 0px 100%;">개요</h5>
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<h5 style="margin: 0px; line-height: 3.428em; color: rgb(34, 61, 103); font-family: 'malgun gothic',dotum,gulim,sans-serif; font-size: 1.166em; background-position: 0px 100%;">개요</h5>
  
 
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 <br> 타원곡선 <math>y^2=x^3-x</math><br>
 
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*   <br>[/pages/2061314/attachments/2299029 MSP1975197gdf732cih44i50000361d01gd578fhc4a.gif]<br>
* <math>y^2=x^3-x</math><br>[/pages/2061314/attachments/2299029 MSP1975197gdf732cih44i50000361d01gd578fhc4a.gif]<br>
 
 
*  유리수해<br><math>E(\mathbb Q)=\{(\infty,\infty), (0,0),(1,0),(-1,0)\} \simeq \frac{\mathbb Z}{2\mathbb Z}\oplus \frac{\mathbb Z}{2\mathbb Z}</math><br>
 
*  유리수해<br><math>E(\mathbb Q)=\{(\infty,\infty), (0,0),(1,0),(-1,0)\} \simeq \frac{\mathbb Z}{2\mathbb Z}\oplus \frac{\mathbb Z}{2\mathbb Z}</math><br>
 
*  주기<br><math>2\omega=4\int_0^1\frac{dx}{\sqrt{1-x^4}}=B(1/2,1/4)=\frac{\Gamma(\frac{1}{2})\Gamma(\frac{1}{4})}{\Gamma(\frac{3}{4})}=\frac{\Gamma(1/4)^2}{\sqrt{2\pi}}=5.24\cdots</math><br><math>2\int_0^1\frac{dx}{\sqrt{x-x^3}}=B(1/2,1/4)=\frac{\Gamma(\frac{1}{2})\Gamma(\frac{1}{4})}{\Gamma(\frac{3}{4})}=5.24\cdots</math><br>
 
*  주기<br><math>2\omega=4\int_0^1\frac{dx}{\sqrt{1-x^4}}=B(1/2,1/4)=\frac{\Gamma(\frac{1}{2})\Gamma(\frac{1}{4})}{\Gamma(\frac{3}{4})}=\frac{\Gamma(1/4)^2}{\sqrt{2\pi}}=5.24\cdots</math><br><math>2\int_0^1\frac{dx}{\sqrt{x-x^3}}=B(1/2,1/4)=\frac{\Gamma(\frac{1}{2})\Gamma(\frac{1}{4})}{\Gamma(\frac{3}{4})}=5.24\cdots</math><br>
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<h5>모듈라 형식</h5>
 
<h5>모듈라 형식</h5>
  
*  유리수체 위의 해의 개수<br><math>E(\mathbb{F}_p)=\{(x,y)\in \mathbb{F}_p^2|E: y^2=x^3+x^2+4x+4\}\cup \{(\infty,\infty})\}</math><br><math>M_p=\#E(\mathbb{F}_p)</math><br><math>a_p=p+1-M_p</math><br>
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*  유리수체 위의 해의 개수<br><math>E(\mathbb{F}_p)=\{(x,y)\in \mathbb{F}_p^2|E: y^2=x^3-x\}\cup \{(\infty,\infty})\}</math><br><math>M_p=\#E(\mathbb{F}_p)</math><br><math>a_p=p+1-M_p</math><br>
 
*  모듈라 형식<br><math>f(\tau)={\eta(4\tau)^2\eta(8\tau)^2}=q\prod_{n=1}^{\infty} (1-q^{4n})^2(1-q^{8n})^2=\sum_{n=1}^{\infty}c_nq^n=q - 2 q^{5 }-3q^9+6q^{13}+2q^{17}+\cdots</math><br>
 
*  모듈라 형식<br><math>f(\tau)={\eta(4\tau)^2\eta(8\tau)^2}=q\prod_{n=1}^{\infty} (1-q^{4n})^2(1-q^{8n})^2=\sum_{n=1}^{\infty}c_nq^n=q - 2 q^{5 }-3q^9+6q^{13}+2q^{17}+\cdots</math><br>
  
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* [[수학사연표 (역사)|수학사연표]]
 
* [[수학사연표 (역사)|수학사연표]]
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* [[타니야마-시무라 추측(정리)]]<br>
 
* [[타니야마-시무라 추측(정리)]]<br>
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* http://www.google.com/dictionary?langpair=en|ko&q=
 
* http://www.google.com/dictionary?langpair=en|ko&q=
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* http://ko.wikipedia.org/wiki/
 
* http://ko.wikipedia.org/wiki/
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* http://www.wolframalpha.com/input/?i=
 
* http://www.wolframalpha.com/input/?i=
 
* [http://dlmf.nist.gov/ NIST Digital Library of Mathematical Functions]
 
* [http://dlmf.nist.gov/ NIST Digital Library of Mathematical Functions]
* [http://www.research.att.com/~njas/sequences/index.html The On-Line Encyclopedia of Integer Sequences]<br>
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* [http://www.research.att.com/%7Enjas/sequences/index.html The On-Line Encyclopedia of Integer Sequences]<br>
 
** http://www.research.att.com/~njas/sequences/?q=
 
** http://www.research.att.com/~njas/sequences/?q=
  
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* http://www.jstor.org/action/doBasicSearch?Query=
 
* http://www.jstor.org/action/doBasicSearch?Query=
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*  도서내검색<br>
 
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*  네이버 뉴스 검색 (키워드 수정)<br>
 
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2009년 12월 26일 (토) 10:44 판

이 항목의 스프링노트 원문주소

 

 

개요
  •  
    타원곡선 \(y^2=x^3-x\)
  •  
    [/pages/2061314/attachments/2299029 MSP1975197gdf732cih44i50000361d01gd578fhc4a.gif]
  • 유리수해
    \(E(\mathbb Q)=\{(\infty,\infty), (0,0),(1,0),(-1,0)\} \simeq \frac{\mathbb Z}{2\mathbb Z}\oplus \frac{\mathbb Z}{2\mathbb Z}\)
  • 주기
    \(2\omega=4\int_0^1\frac{dx}{\sqrt{1-x^4}}=B(1/2,1/4)=\frac{\Gamma(\frac{1}{2})\Gamma(\frac{1}{4})}{\Gamma(\frac{3}{4})}=\frac{\Gamma(1/4)^2}{\sqrt{2\pi}}=5.24\cdots\)
    \(2\int_0^1\frac{dx}{\sqrt{x-x^3}}=B(1/2,1/4)=\frac{\Gamma(\frac{1}{2})\Gamma(\frac{1}{4})}{\Gamma(\frac{3}{4})}=5.24\cdots\)
  • 모듈라 군, j-invariant and the singular moduli 의 special values 부분과 비교

 

모듈라 형식
  • 유리수체 위의 해의 개수
    \(E(\mathbb{F}_p)=\{(x,y)\in \mathbb{F}_p^2|E: y^2=x^3-x\}\cup \{(\infty,\infty})\}\)
    \(M_p=\#E(\mathbb{F}_p)\)
    \(a_p=p+1-M_p\)
  • 모듈라 형식
    \(f(\tau)={\eta(4\tau)^2\eta(8\tau)^2}=q\prod_{n=1}^{\infty} (1-q^{4n})^2(1-q^{8n})^2=\sum_{n=1}^{\infty}c_nq^n=q - 2 q^{5 }-3q^9+6q^{13}+2q^{17}+\cdots\)

 

 

재미있는 사실

 

 

 

역사

 

 

메모

 

 

관련된 항목들

 

 

수학용어번역

 

 

사전 형태의 자료

 

 

관련논문

 

관련도서 및 추천도서

 

 

관련기사

 

 

블로그